Integrand size = 20, antiderivative size = 151 \[ \int \frac {\left (a+b x+c x^2\right )^2}{(d+e x)^6} \, dx=-\frac {\left (c d^2-b d e+a e^2\right )^2}{5 e^5 (d+e x)^5}+\frac {(2 c d-b e) \left (c d^2-b d e+a e^2\right )}{2 e^5 (d+e x)^4}-\frac {6 c^2 d^2+b^2 e^2-2 c e (3 b d-a e)}{3 e^5 (d+e x)^3}+\frac {c (2 c d-b e)}{e^5 (d+e x)^2}-\frac {c^2}{e^5 (d+e x)} \]
[Out]
Time = 0.07 (sec) , antiderivative size = 151, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.050, Rules used = {712} \[ \int \frac {\left (a+b x+c x^2\right )^2}{(d+e x)^6} \, dx=-\frac {-2 c e (3 b d-a e)+b^2 e^2+6 c^2 d^2}{3 e^5 (d+e x)^3}+\frac {(2 c d-b e) \left (a e^2-b d e+c d^2\right )}{2 e^5 (d+e x)^4}-\frac {\left (a e^2-b d e+c d^2\right )^2}{5 e^5 (d+e x)^5}+\frac {c (2 c d-b e)}{e^5 (d+e x)^2}-\frac {c^2}{e^5 (d+e x)} \]
[In]
[Out]
Rule 712
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {\left (c d^2-b d e+a e^2\right )^2}{e^4 (d+e x)^6}+\frac {2 (-2 c d+b e) \left (c d^2-b d e+a e^2\right )}{e^4 (d+e x)^5}+\frac {6 c^2 d^2+b^2 e^2-2 c e (3 b d-a e)}{e^4 (d+e x)^4}-\frac {2 c (2 c d-b e)}{e^4 (d+e x)^3}+\frac {c^2}{e^4 (d+e x)^2}\right ) \, dx \\ & = -\frac {\left (c d^2-b d e+a e^2\right )^2}{5 e^5 (d+e x)^5}+\frac {(2 c d-b e) \left (c d^2-b d e+a e^2\right )}{2 e^5 (d+e x)^4}-\frac {6 c^2 d^2+b^2 e^2-2 c e (3 b d-a e)}{3 e^5 (d+e x)^3}+\frac {c (2 c d-b e)}{e^5 (d+e x)^2}-\frac {c^2}{e^5 (d+e x)} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 160, normalized size of antiderivative = 1.06 \[ \int \frac {\left (a+b x+c x^2\right )^2}{(d+e x)^6} \, dx=-\frac {6 c^2 \left (d^4+5 d^3 e x+10 d^2 e^2 x^2+10 d e^3 x^3+5 e^4 x^4\right )+e^2 \left (6 a^2 e^2+3 a b e (d+5 e x)+b^2 \left (d^2+5 d e x+10 e^2 x^2\right )\right )+c e \left (2 a e \left (d^2+5 d e x+10 e^2 x^2\right )+3 b \left (d^3+5 d^2 e x+10 d e^2 x^2+10 e^3 x^3\right )\right )}{30 e^5 (d+e x)^5} \]
[In]
[Out]
Time = 5.11 (sec) , antiderivative size = 179, normalized size of antiderivative = 1.19
method | result | size |
risch | \(\frac {-\frac {c^{2} x^{4}}{e}-\frac {c \left (b e +2 c d \right ) x^{3}}{e^{2}}-\frac {\left (2 a c \,e^{2}+b^{2} e^{2}+3 b c d e +6 c^{2} d^{2}\right ) x^{2}}{3 e^{3}}-\frac {\left (3 a b \,e^{3}+2 d \,e^{2} a c +b^{2} d \,e^{2}+3 b c e \,d^{2}+6 c^{2} d^{3}\right ) x}{6 e^{4}}-\frac {6 a^{2} e^{4}+3 a b d \,e^{3}+2 a c \,d^{2} e^{2}+b^{2} d^{2} e^{2}+3 d^{3} e b c +6 c^{2} d^{4}}{30 e^{5}}}{\left (e x +d \right )^{5}}\) | \(179\) |
norman | \(\frac {-\frac {c^{2} x^{4}}{e}-\frac {\left (b c e +2 c^{2} d \right ) x^{3}}{e^{2}}-\frac {\left (2 a c \,e^{2}+b^{2} e^{2}+3 b c d e +6 c^{2} d^{2}\right ) x^{2}}{3 e^{3}}-\frac {\left (3 a b \,e^{3}+2 d \,e^{2} a c +b^{2} d \,e^{2}+3 b c e \,d^{2}+6 c^{2} d^{3}\right ) x}{6 e^{4}}-\frac {6 a^{2} e^{4}+3 a b d \,e^{3}+2 a c \,d^{2} e^{2}+b^{2} d^{2} e^{2}+3 d^{3} e b c +6 c^{2} d^{4}}{30 e^{5}}}{\left (e x +d \right )^{5}}\) | \(181\) |
gosper | \(-\frac {30 c^{2} x^{4} e^{4}+30 x^{3} b c \,e^{4}+60 x^{3} c^{2} d \,e^{3}+20 x^{2} a c \,e^{4}+10 x^{2} b^{2} e^{4}+30 x^{2} b c d \,e^{3}+60 x^{2} c^{2} d^{2} e^{2}+15 x a b \,e^{4}+10 x a c d \,e^{3}+5 x \,b^{2} d \,e^{3}+15 x b c \,d^{2} e^{2}+30 x \,c^{2} d^{3} e +6 a^{2} e^{4}+3 a b d \,e^{3}+2 a c \,d^{2} e^{2}+b^{2} d^{2} e^{2}+3 d^{3} e b c +6 c^{2} d^{4}}{30 \left (e x +d \right )^{5} e^{5}}\) | \(193\) |
parallelrisch | \(\frac {-30 c^{2} x^{4} e^{4}-30 x^{3} b c \,e^{4}-60 x^{3} c^{2} d \,e^{3}-20 x^{2} a c \,e^{4}-10 x^{2} b^{2} e^{4}-30 x^{2} b c d \,e^{3}-60 x^{2} c^{2} d^{2} e^{2}-15 x a b \,e^{4}-10 x a c d \,e^{3}-5 x \,b^{2} d \,e^{3}-15 x b c \,d^{2} e^{2}-30 x \,c^{2} d^{3} e -6 a^{2} e^{4}-3 a b d \,e^{3}-2 a c \,d^{2} e^{2}-b^{2} d^{2} e^{2}-3 d^{3} e b c -6 c^{2} d^{4}}{30 e^{5} \left (e x +d \right )^{5}}\) | \(194\) |
default | \(-\frac {a^{2} e^{4}-2 a b d \,e^{3}+2 a c \,d^{2} e^{2}+b^{2} d^{2} e^{2}-2 d^{3} e b c +c^{2} d^{4}}{5 e^{5} \left (e x +d \right )^{5}}-\frac {c^{2}}{e^{5} \left (e x +d \right )}-\frac {2 a c \,e^{2}+b^{2} e^{2}-6 b c d e +6 c^{2} d^{2}}{3 e^{5} \left (e x +d \right )^{3}}-\frac {2 a b \,e^{3}-4 d \,e^{2} a c -2 b^{2} d \,e^{2}+6 b c e \,d^{2}-4 c^{2} d^{3}}{4 e^{5} \left (e x +d \right )^{4}}-\frac {c \left (b e -2 c d \right )}{e^{5} \left (e x +d \right )^{2}}\) | \(195\) |
[In]
[Out]
none
Time = 0.42 (sec) , antiderivative size = 219, normalized size of antiderivative = 1.45 \[ \int \frac {\left (a+b x+c x^2\right )^2}{(d+e x)^6} \, dx=-\frac {30 \, c^{2} e^{4} x^{4} + 6 \, c^{2} d^{4} + 3 \, b c d^{3} e + 3 \, a b d e^{3} + 6 \, a^{2} e^{4} + {\left (b^{2} + 2 \, a c\right )} d^{2} e^{2} + 30 \, {\left (2 \, c^{2} d e^{3} + b c e^{4}\right )} x^{3} + 10 \, {\left (6 \, c^{2} d^{2} e^{2} + 3 \, b c d e^{3} + {\left (b^{2} + 2 \, a c\right )} e^{4}\right )} x^{2} + 5 \, {\left (6 \, c^{2} d^{3} e + 3 \, b c d^{2} e^{2} + 3 \, a b e^{4} + {\left (b^{2} + 2 \, a c\right )} d e^{3}\right )} x}{30 \, {\left (e^{10} x^{5} + 5 \, d e^{9} x^{4} + 10 \, d^{2} e^{8} x^{3} + 10 \, d^{3} e^{7} x^{2} + 5 \, d^{4} e^{6} x + d^{5} e^{5}\right )}} \]
[In]
[Out]
Timed out. \[ \int \frac {\left (a+b x+c x^2\right )^2}{(d+e x)^6} \, dx=\text {Timed out} \]
[In]
[Out]
none
Time = 0.20 (sec) , antiderivative size = 219, normalized size of antiderivative = 1.45 \[ \int \frac {\left (a+b x+c x^2\right )^2}{(d+e x)^6} \, dx=-\frac {30 \, c^{2} e^{4} x^{4} + 6 \, c^{2} d^{4} + 3 \, b c d^{3} e + 3 \, a b d e^{3} + 6 \, a^{2} e^{4} + {\left (b^{2} + 2 \, a c\right )} d^{2} e^{2} + 30 \, {\left (2 \, c^{2} d e^{3} + b c e^{4}\right )} x^{3} + 10 \, {\left (6 \, c^{2} d^{2} e^{2} + 3 \, b c d e^{3} + {\left (b^{2} + 2 \, a c\right )} e^{4}\right )} x^{2} + 5 \, {\left (6 \, c^{2} d^{3} e + 3 \, b c d^{2} e^{2} + 3 \, a b e^{4} + {\left (b^{2} + 2 \, a c\right )} d e^{3}\right )} x}{30 \, {\left (e^{10} x^{5} + 5 \, d e^{9} x^{4} + 10 \, d^{2} e^{8} x^{3} + 10 \, d^{3} e^{7} x^{2} + 5 \, d^{4} e^{6} x + d^{5} e^{5}\right )}} \]
[In]
[Out]
none
Time = 0.28 (sec) , antiderivative size = 192, normalized size of antiderivative = 1.27 \[ \int \frac {\left (a+b x+c x^2\right )^2}{(d+e x)^6} \, dx=-\frac {30 \, c^{2} e^{4} x^{4} + 60 \, c^{2} d e^{3} x^{3} + 30 \, b c e^{4} x^{3} + 60 \, c^{2} d^{2} e^{2} x^{2} + 30 \, b c d e^{3} x^{2} + 10 \, b^{2} e^{4} x^{2} + 20 \, a c e^{4} x^{2} + 30 \, c^{2} d^{3} e x + 15 \, b c d^{2} e^{2} x + 5 \, b^{2} d e^{3} x + 10 \, a c d e^{3} x + 15 \, a b e^{4} x + 6 \, c^{2} d^{4} + 3 \, b c d^{3} e + b^{2} d^{2} e^{2} + 2 \, a c d^{2} e^{2} + 3 \, a b d e^{3} + 6 \, a^{2} e^{4}}{30 \, {\left (e x + d\right )}^{5} e^{5}} \]
[In]
[Out]
Time = 0.09 (sec) , antiderivative size = 221, normalized size of antiderivative = 1.46 \[ \int \frac {\left (a+b x+c x^2\right )^2}{(d+e x)^6} \, dx=-\frac {\frac {6\,a^2\,e^4+3\,a\,b\,d\,e^3+2\,a\,c\,d^2\,e^2+b^2\,d^2\,e^2+3\,b\,c\,d^3\,e+6\,c^2\,d^4}{30\,e^5}+\frac {x\,\left (b^2\,d\,e^2+3\,b\,c\,d^2\,e+3\,a\,b\,e^3+6\,c^2\,d^3+2\,a\,c\,d\,e^2\right )}{6\,e^4}+\frac {c^2\,x^4}{e}+\frac {x^2\,\left (b^2\,e^2+3\,b\,c\,d\,e+6\,c^2\,d^2+2\,a\,c\,e^2\right )}{3\,e^3}+\frac {c\,x^3\,\left (b\,e+2\,c\,d\right )}{e^2}}{d^5+5\,d^4\,e\,x+10\,d^3\,e^2\,x^2+10\,d^2\,e^3\,x^3+5\,d\,e^4\,x^4+e^5\,x^5} \]
[In]
[Out]